Реши систему уровнения x +2y/10-x+4y/3=-8 2x-3y/2-x+y/6=0.

$\left \{ {\frac{x+2y}{10}-\frac{x+4y}{3}=-8|*30} \atop {\frac{2x-3y}{2}-\frac{x+y}{6}=0|*6}} \right. \left \{ {3(x+2y)-10(x+4y)=-30*8} \atop {3(2x-3y)-(x+y)=0} \right.\left \{ {3x+6y-10x-40y=-240} \atop {6x-9y-x-y=0} \right.=\ \textgreater \ \\\\=\ \textgreater \ \left \{ {{-7x-34y=-240|*5} \atop {5x-10y=0|*7}} \right. \left \{ {{-35x-170y=-1200} \atop {35x-70y=0}} \right. =\ \textgreater \ Skladivaem=\ \textgreater \ \\\\=\ \textgreater \ \left \{ {{-240y=-1200} \atop {35x-70y=0}} \right.\left \{ {{y=5} \atop {35x-70*5=0}} \right.\left \{ {{y=5} \atop {35x=70*5}} \right.=\ \textgreater \$
$=\ \textgreater \ \left \{ {{y=5} \atop {35x=350}} \right. \left \{ {{y=5} \atop {x=\frac{350}{35}}} \right. \left \{ {{y=5} \atop {x=10}} \right.$
Ответ:(10;5)