1) 3.4+2y=7(y-2.3) 2) 0.2(7-2y)=2.3-0.3*(y-6)

Question

1) 3.4+2y=7(y-2.3)
2) 0.2(7-2y)=2.3-0.3*(y-6)

Answer 1

3.4+2y=7(y-2.3)
3.4+2y=7y-16.1
3.4+16.1=7y-2y
19.5=5y
y=19.5:5
y=3.9

0.2(7-2y)=2.3-0.3(y-6)
1.4-0.4y=2.3-0.3y-1.8
1.4-2.3+1.8=-0.3y+0.4y
0.9=0.1y
y=0.9:0,1
y=9