Arccos (-1/2) - arcsin корень 3/2 4 arctg 1 + 3 arctg (-1/корень3)

Question

Arccos (-1/2) - arcsin корень 3/2
4 arctg 1 + 3 arctg (-1/корень3)

Answer 1

Arccos (-1/2) - arcsin (√( 3/2))=π-π/3 -π/3=π/3

4 arctg 1 + 3 arctg (-1/√3)= 4·π/4-3·π/6= π-π/2=π/2