SABC-правильная треугольная пирамида,SA=SB=SC=m,SO_|_(ABC),
CH_|_AB,SH_|_AB,SO=SC*sinCO=SC*cosCO=2/3*CH⇒CH=3m/4
OH=m/4
SH=√(SO²+OH²)=√(3m²/4+m²/16)=m√13/4
AB=AC-BC=CH/sin60=3m/4:√3/2=√3m/2
Sосн=1/2*AB*CH=1/2*√3m/2*3m/4=3√3m²/16
S бок=3*S(ASB)=3*1/2*AB*SH=3/2*√3m/2*m√13/4=3√39m²/16
Sпол=Sосн+Sбок=3√3m²/16+3√39m²/16=3√3m²/16*(1+√13)