ОДЗ: х≠2
х≠3
0[/tex]
Разложим на множители:
5x²-25x+31=0
D=625-4*5*31=625-620=5
x₁=(25-√5)/10≈2.27
x₂=(25+√5)/10≈2.72
+ - + - +
------- 2 --------- (25-√5)/10 ----------- (25+√5)/10 -------- 3 ----------
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x∈(-∞; 2)U[(25-√5)/10; (25+√5)/10]U(3; +∞)