Решить систему уравнения {10-6(2x+5)=6y-13{4y-63=5(4x-2y)+2

\left \{ {{10-12x-30=6y-13} \atop {4y-63=20x-10y+2}} \right. <=>\\\ <=>\left \{ {{12x+6y=-7|*5} \atop {20x-14y=-65|*3}} \right.<=>\left \{ {{60x+30y=-35} \atop {60x-42y=-195}} \right. " alt="\left \{ {{10-6(2x+5)=6y-13} \atop {4y-63=5(4x-2y)+2}} \right. <=>\left \{ {{10-12x-30=6y-13} \atop {4y-63=20x-10y+2}} \right. <=>\\\ <=>\left \{ {{12x+6y=-7|*5} \atop {20x-14y=-65|*3}} \right.<=>\left \{ {{60x+30y=-35} \atop {60x-42y=-195}} \right. " align="absmiddle" class="latex-formula">

вычтем из первого уравнения второе

72y=160

$y=2\frac{2}{9}$

$12x+6*2\frac{2}{9}=-7\\\ 12x+6*\frac{20}{9}=-7\\\ 12x+2*\frac{20}{3}=-7\\\ 12x+\frac{40}{3}=-7\\\ 12x=-7-13\frac{1}{3}\\\ 12x=-20\frac{1}{3}\\\ x=-\frac{61}{3}:12\\\ x=-\frac{61}{36}\\\ x=-1\frac{25}{36}$