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Решение cos(πx/6 + 5/6π) = - 1/2 πx/6 + 5/6π = (+ -) arccos(- 1/2) + 2πk, k ∈ Z πx/6 + (5/6)π = (+ -) (2π/3) + 2πk, k ∈ Z πx/6 = (+ -) (2π/3) - (5/6)π + 2πk, k ∈ Z πx = (+ -) (4π) - 5π + 12πk, k ∈ Z x = (+ -) (4) - 5π + 12k, k ∈ Z