Срочно!помогите решить:
Α-β=-π/2⇒α=β-π/2 sin(β-π/2)cosβ=-1/4 -cos²β=-1/4 cos²β=1/4 cosβ=-1/2⇒β=2π/3⇒α=2π/3-π/2=π/6 sin(α+β)=sin(π/6+2π/3)=sin5π/6=1/2 cosβ=1/2⇒β=π/3⇒α=π/3-π/2=-π/6 sin(α+β)=sin(-π/6+π/3)=sinπ/6=1/2