Tg31П/6= (2 TgП/6 - TgП/3): cosП/6= Ctg13П/4= cos19П/3=

Question

Tg31П/6=

(2 TgП/6 - TgП/3): cosП/6=

Ctg13П/4=

cos19П/3=

Answer 1

Tg31П/6=tg(31pi/6-5pi)=tgpi/6=1/sqrt(3)

(2 TgП/6 - TgП/3): cosП/6=(2sqrt(3)-sqrt(3)/3)*2/sqrt(3)=4-2/3=10/3

Ctg13П/4=ctg(13pi/4-3pi)=ctgpi/4=1

cos19П/3=cos(19pi/3-6pi)=cospi/3=1/2