{█(х-у=2, х^2-ху+у^2=7 помогите решить систему уравнений

$\left \{ {{x-y=2} \atop {x^{2}-xy+y^{2}=7}} \right. \left \{ {{x-y=2} \atop {(x-y)^{2}+xy=7}} \right. \left \{ {{x-y=2} \atop {2^{2}+xy=7}} \right. \left \{ {{x=2+y} \atop {xy=7-4}} \right. \left \{ {{x=2+y} \atop {(y+2)y=3}} \right. \\ y^{2}+2y-3=0 \\ D=1+3=4 \\ y_{1}=-1+2=1 -\ \textgreater \ x_{1}=2+y_{1}=2+1=3 \\ y_{2}=-1-2=-3 -\ \textgreater \ x_{2}=2+y_{2}=2-3=-1$
Ответ: (3;1) и (-1;-3)