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Question

Дано ответов: 2

cot159263_zn · Answer 1 · 2018-04-25T14:49:15+0000

а) 2 13\30 - (1 1\10+1\5) = 1 2/15

1 1\10+1\5 = 1 1/10 + 2/10 = 1 3/10
2 13/30 - 1 3/10 = 2 13/30 - 1 9/30 = 1 4/30 = 1 2/15

б) 2 8\15-(1 3\10+2\5) = 5/6

1 3\10+2\5 = 1 3/10 + 4/10 = 1 7/10
2 8/15 - 1 7/10 = 2 16/30 - 1 21/30 = 1 46/30 - 1 21/30 = 25/30 = 5/6

в) 4 14\45-1 7\15-3\5 = 4 14/45 - 1 21/45 - 27/45 = 3 59/45 - 1 21/45 - 27/45 = = 2 38/45 - 1 21/45 = 1 17/45

г) 4 11\30-2 9\20-1\10 = 4 22/60 - 2 27/60 - 6/60 = 4 22/60 - 2 21/60 = 2 1/60

piksaeva85znayka_zn · Answer 2 · 2018-04-25T14:49:15+0000

$2\frac{13}{30}-( 1\frac{1}{10}+ \frac{1}{5})= [tex] 1\frac{2}{15}$
1) 1 \frac{1}{10}+ \frac{1}{5}= 1\frac{1}{10}+ \frac{2}{10}= 1\frac{3}{10} [/tex]
2) $2\frac{13}{30}- 1\frac{3}{10}= 2\frac{13}{30}- 1\frac{9}{30}= 1\frac{4}{30}= 1\frac{2}{15}$
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$2\frac{8}{15}-( 1\frac{3}{10}+ \frac{2}{5})=\frac{5}{6}$
1) $1\frac{3}{10}+ \frac{2}{5}= 1\frac{3}{10}+ \frac{4}{10}=1\frac{7}{10}$
2) $2\frac{8}{15}-1\frac{7}{10}= 2\frac{16}{30}- 1\frac{21}{30}=1\frac{46}{30}- 1\frac{21}{30}= \frac{25}{30}= \frac{5}{6}$
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$4\frac{14}{45}- 1\frac{7}{15}- \frac{3}{5}= [tex] 2\frac{11}{45}$
1)

[tex] 4\frac{14}{45}- 1\frac{21}{45}= =[tex] 3\frac{59}{45}-1\frac{21}{45}= 2\frac{38}{45} " alt=" 4\frac{14}{45}- 1\frac{7}{15}=[tex] 4\frac{14}{45}- 1\frac{21}{45}= =[tex] 3\frac{59}{45}-1\frac{21}{45}= 2\frac{38}{45} " align="absmiddle" class="latex-formula">
2)2\frac{38}{45} [/tex] -\frac{3}{5}= 2\frac{38}{45}- \frac{27}{45}=2 \frac{11}{45} [/tex]
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$4\frac{11}{30}- 2\frac{9}{20}- \frac{1}{10}=$ 1 \frac{49}{60} [/tex]
1) $4\frac{11}{30}-2 \frac{9}{20}=4 \frac{22}{60}- 2\frac{27}{60}=3 \frac{82}{60}- 2\frac{27}{60}=1 \frac{55}{60}$
2)1 \frac{55}{60} [/tex]- $\frac{1}{10}=1 \frac{55}{60}- \frac{6}{60}=1 \frac{49}{60}$