(2х+3)^2-(х-1)^2 решите)

Question

(2х+3)^2-(х-1)^2 решите)

Answer 1

4x^2+12x+9-x^2+2x-1=3x^2+14x+8; 3x^2+14x+8=0; D=14^2-4×3×8=196-96=100=10^2; x1=(-14-10)/2*3=-4; x2=(-14+10)/2*3=-4/6=-2/3

Comments

спасибо