Sin⁡2α-tan⁡α= cos⁡2α∙tan⁡α

Question

Sin⁡2α-tan⁡α= cos⁡2α∙tan⁡α

Answer 1

2sinacosa-sina/cosa=(2sinacos²a-sina)/cosa=sina(2cos²a-1)/cosa=
=cos2a*tga