X^2-17x+42=0 uyyyyyyyyyyyyy

Question

X^2-17x+42=0 uyyyyyyyyyyyyy

Answer 1

X²-17x+42=0
a=1,b=-17, c=42

D=b²-4ac, D=(-17)²-4.1.42=289-168=121,√D=√121=11
x1=(17+11)/2=28/2=14
x2=(17-11)/2=6/2=3
x1=14,x2=3
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Answer 2

Д=17^2-4×42=121=11(корень 121)
Д>0
х=(-17-11)÷2=-14
х=(-17+11)÷2=-3
Ответ: х1=-14
х2=-3