Help please 6sin(-405°)-cos405°×ctg1110°=

Question

Help please

6sin(-405°)-cos405°×ctg1110°=

Answer 1

6sin(-405°)-cos405°×ctg1110°= -6sin(360+45)-cos(360+45)°×ctg(360*3+30)°=  -6sin45-cos45*сtg30= (см. во вложении продолжение) 

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