(x+4)^2-(x+1)(x-2)=2x-3

Question

(x+4)^2-(x+1)(x-2)=2x-3

Answer 1

( x + 4 )^2 - ( x + 1 )( x - 2 ) = 2x - 3
x^2 + 8x + 16 - ( x^2 - 2x + x - 2 ) = 2x - 3
x^2 + 8x + 16 - x^2 + x + 2 = 2x - 3
9x + 18 = 2x - 3
7x = - 21
x = - 3

Answer 2

Х*2+8х+16-(х*2-2х+х-2)-2х+3=0
х*2+8х+16-х*2+2х-х+2-2х+3=0 7Х=21 х=3