P+q/p-q - p-q/p+q при p=2; q=корень из 3

Question

P+q/p-q - p-q/p+q при p=2; q=корень из 3

Answer 1

(p+q)/(p-q) - (p-q)/(p+q)=((p+q)(p+q)-(p-q)(p-q))/(p-q)(p+q)=
=(p²+2pq+q²-p²+2pq-q²)/(p²-q²)=4pq/(p²-q²)

p=2,q=√3 ≡ 4.2.√3/(2²-(√3)²)=8.√3/(4-3)=8.√3