Помогите решить (x+13)^2=x^2+(x+4)^2+x^2+81
(x+13)² =x²+x²+8x+16+x²+81 x²+26x+169 =3x²+8x+97 x² -3x²+26x -8x+169 -97 =0 -2x² +18x +72 =0, :(-2) x² -9x -36 =0 D =81 +144 =225 =15² x1 =(9 -15)/2 = -3 x2 =(9 +15)/2 =12 ответ: x= -3, x =12