√2sinx-√2cosx=2 решить уравнение!
√2/2 ·sinx -√2/2 ·cosx=1 sinx·cosπ/4 - cosx·sinπ/4 =1 sin(x-π/4) =1 x-π/4=π/2 + 2πk ; k∈Z x = 3/4 ·π + 2πk ; k∈Z