ПРЕОБРАЗУЙТЕ ТРЕХЧЛЕН В КВАДРАТ ДВУЧЛЕНА

Решите задачу:

$16t^2 +24nt+9n^2 = (4t)^2+2\cdot 4t\cdot 3n+(3n)^2 =(4t+3n)^2 \\ 81d^2 +36dp+4p^2 = (9d)^2 +2 \cdot 9d\cdot 2p + (2p)^2 = (9d+2p)^2 \\ 16b^2 -56bc +49c^2 = (4b)^2 -2\cdot 4b \cdot 7c + (7c)^2 = (4b-7c)^2 \\ a^2b^2-8abc+16c^2 = (ab)^2 -2\cdot ab\cdot 4c + (4c)^2 = (ab-4c)^2 \\ 16b^4 +24b^2c^2 +9c^4 = (4b^2)^2 +2\cdot 4b^2 \cdot 3c^2 + (3c^2)^2 =(4b^2 +3c^2)^2 \\ b^8 -14b^4c^2 +49c^4 = (b^4)^2 -2\cdot b^4\cdot 7c^2 + (7c^2)^2=(b^4 -7c^2)^2$