((х + √х)³)' = 3(x+√x)² * 1(/2√х)= 3(х +√х)²/(2√х)
((1/х +1)³)' = 3(1/x +1)² * (-1/х²)= -3(1/х +1)/х²
(√(9 -2х)' = 1/2√9 -2х) * (-2х) = -2х/2√(9 -2х) = -х/√(9-2х)
((4-√х)⁵)' = 5(4-√x)⁴ * (1/2√х) = -5(4 - √х)⁴/(2√х)
((х - 2√х)⁴)' = 4(x - 2√x)³ * -2/(2√x) = 4(x- 2√x)/√х