Решите неравенства: log0,3(x-1)+log0,3(x+1)>log0,3(2x-1)

Question

Решите неравенства:

log0,3(x-1)+log0,3(x+1)>log0,3(2x-1)

Answer 1

log(0,3)10-log(0,3)3 =
=log(0,3)10/3 = log(0,3) (3/10)^-1 = -1 log(0,3) 0,3 = -1 *1 = -1