Срочно!!!' Решите неравенство !!!!!
X-1≥0⇒x≥1 x+2≥0⇒x≥-2 x∈[1;∞) 3√(x-1)>1+√(x+2) 9(x-1)>1+2√(x+2)+x+2 9x-9-x-3>2√(x+2) 8x-12>2√(x+2) 4x-6>√(x+2) 16x²-48x+36>x+2 16x²-49x+34>0 D=2401-2176=225 x1=(49-15)/32=17/16 x2=(49+15)/32=2 x<1/16 U x>2 x∈[1;17/16) U (2;∞)