(x^2-x)^2-5(x^2-x)-6=0
у=x^2-x
у²-5у-6=0
D = b² - 4ac = (-5)2 - 4·1·(-6) = 25 + 24 = 49
у1 = (5 - √49)/(2·1) = (5 - 7)2 = -2/2 = -1
у1 = (5 + √49)/(2·1) = (5 + 7)2 = 12/2 = 6
х²-х=-1
х²-х+1=0
D = b² - 4ac = (-1)2 - 4·1·1 = 1 - 4 = -3 -решений нет
х²-х=6
х²-х-6=0
D = b² - 4ac = (-1)2 - 4·1·(-6) = 1 + 24 = 25
x1 = (1 - √25)/(2·1) = (1 - 5)/2 = -4/2 = -2
x1 = (1 +√25)/(2·1) = (1 + 5)/2 = 6/2 = 3