Log1/3(log2((х-1)/(х-2)))>-1
ОДЗ (x-1)/(x-2)>0 x=1 U x=2 x∈(-∞;1) U (2;∞) log(2)[(x-1)/(x-2)]<3<br>(x-1)/(x-2)<8<br>(x-1)/(x-2)-8<0<br>(x-1-8x+16)/(x-2)<0<br>(15-7x)/(x-2)<0<br>x=15/7 x=2 2x∈(2;2 1/7)