(4целых 1\6х+11 целых 1\4)*4\15=2\3х+5 целых 2\3

Решите задачу:

$(4\frac{1}{6}x+11\frac{1}{4})\frac{4}{15}=\frac{2}{3}x+5\frac{2}{3}$
$(\frac{25}{6}x+\frac{45}{4})\frac{4}{15}=\frac{2}{3}x+\frac{17}{3}$
$\frac{25}{6}x*\frac{4}{15}+\frac{45}{4}*\frac{4}{15}=\frac{2}{3}x+\frac{17}{3}$
$\frac{5}{3}x*\frac{2}{3}+3=\frac{2}{3}x+\frac{17}{3}$
$\frac{10}{9}x=\frac{2}{3}x+\frac{17}{3}-3$
$\frac{10}{9}x-\frac{2}{3}x=5\frac{2}{3}-3$
$\frac{10}{9}x-\frac{6}{9}x=2\frac{2}{3}$
$\frac{4}{9}x=2\frac{2}{3}$
$\frac{4}{9}x=\frac{8}{3}$
$x=\frac{8}{3}:\frac{4}{9}$
$x=\frac{8}{3}*\frac{9}{4}$
$x=6$