Log12 1440- log12 10+ 3log9 16

Question

Log12 1440- log12 10+ 3log9 16

Answer 1

Решение тут...............................

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Answer 2

㏒12(1440)-㏒12()10+㏒9(16)=㏒12(1440\10)+㏒9(16³)=
㏒12(144)+㏒9(4096)=2+㏒9(4096)=㏒9(81)+㏒9(4096)=
㏒9(81·4096)=㏒9(331776)