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f'(x)=((x-1)'(x²+1)-(x²+1)'(x-1))/(x²+1)²= (x(x²+1)-2x(x-1))/(x²+1)² =
=( x³+x-2x²+2x)/(x²+1)²= (x³-2x²+3x)/(x²+1)²
f'(1)= (1-2+3)/(1+1)²=2/2=1