Cos4x+ cos2x=0 помогите пож
(cos2x)^2-(sin2x)^2+cos2x=0
(cos2x)^2-1+(cos2x)^2+cos2x=0
2(cos2x)^2+cos2x-1=0
D=1+8=9
cos2x= -1 cos2x=0,5
2x=π+2πn |:2 2x=π/3+2πn |:2
x=π/2+πn x=π/6+πn
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