Решите уравнение y^3+y-2=0
Y^3 + y - 2 = 0 y^3 - y^2 + y^2 - y + 2y - 2 = y^2(y - 1) + y(y - 1) + 2(y - 1) = =(y - 1) (y^2 + y - 2) = 0 1) y - 1 = 0, y1 = 1 2) y^2 + y - 2 = 0 По теореме Виета y2 = -2, y3 = 1