{x/3-y/2=-3 x/2+y/5=5

Question

{x/3-y/2=-3 x/2+y/5=5

Answer 1

(2х-3у)/6=-3     /*6
(5х+2у)/10=5   /*10

2х-3у=-18
5х+2у=50

х=(3у-18)/2
(5(3у-18))/2 +2у=50    /*2

15у-90+4у=100
19у=190
у=10

х=(3*10-18)/2, 
х=6

Ответ: (6;10)