Решите уравнение 2х³-5х²-3х=0
X( 2x^2 - 5x - 3) = 0 x=0 2x^2 - 5x - 3 = 0 D = b^2 - 4ac = 25 + 24 = 49 = 7^2 x1 = ( 5 + 7) / 4 = 3 x2 = ( 5 - 7) / 4 = - 0,5 Ответ: x1 = 3, x2 = - 0,5, x3 = 0