5^x+1 + 5^x + 5^x-1 = 31 27^1+2x > (1/9)^2+x

$5^{x+1} + 5^{x} + 5^{x-1} =31 5^{x-1} *( 5^{2}+5+1 )=31 5^{x-1} *31=31 5^{x-1} =1 5^{x-1} = 5^{0}$
x-1=0
x=1

или

$5^{x+1} + 5^{x} + 5^{x-1} =31$
$5^{x}* 5^{1} +5^{x} + 5^{x}* \frac{1}{5} =31$
$5^{x}*(5+1+ \frac{1}{5} ) =31 5^{x}*6 \frac{1}{5} =31 5^{x} =5 ^{1}$
x=1

2.

( \frac{1}{9} ) ^{2+x} ( 3^{3} )^{1+2x} >( 3^{-2} ) ^{2+x} 3^{3+6x} > 3^{-4-2x} " alt=" 27^{1+2x} >( \frac{1}{9} ) ^{2+x} ( 3^{3} )^{1+2x} >( 3^{-2} ) ^{2+x} 3^{3+6x} > 3^{-4-2x} " align="absmiddle" class="latex-formula">
3+6x>-4-2x. 8x>-7

- \frac{7}{8} " alt="x>- \frac{7}{8} " align="absmiddle" class="latex-formula">