Sin(п/2+4х)=1 решите уравнение
Cos4x=1 4x=2πn x=πn/2,n∈z --------------------------
Sin(π/2+4x)=1 1)sinπ/2=1 2)sin(x+2k.π)=sinx π/2+4x=π/2+2k.π, k∈Z 4x=2k.π x=k.π/2, k∈Z (k=0,1,-1,2,-2,.........) ==========