Решить систему.
2(x+y)=40 xy=51 ------------- x+y=20 xy=51 ----------- x=20-y (20-y).y=51,20y-y²=51,y²-20y+51=0,D=400-204=196,√D=√196=14 y1=(20+14)/2=34/2=17, y2=(20-14)/2=6/2=3 x1=20-17=3, x2=20-3=17 /x,y/=/3,17/ ili /x,y/=/17,3/