Помогите! Решите неравенство: x^2+7x-19/x-3 ⩾ 1
(x²+7x-19)/(x-3)-1≥0 (x²+7x-19-x+3)/(x-3)≥0 (x²+6x-16)/(x-3)≥0 x1=x2=-6 U x1*x2=-16⇒x1=-8 U x2=2 x-3=0⇒x=3 _ + _ + ------------------[-8]---------[2]-----------------(3)------------------ x∈[-8;2] U (3;∞)