Решить неравенство 3-x/4<5-2x/18

Решите задачу:

$\frac{3-x}{4} \ \textless \ \frac{5-2x}{18} \\\\ \frac{9(3-x)}{4\cdot 9} -\frac{2(5-2x)}{18\cdot 2} \ \textless \ 0\\\\ \frac{27-9x-10+4x}{36} \ \textless \ 0\\\\ \frac{17-5x}{36} \ \textless \ 0\; \Rightarrow \quad tak\; \; kak\; \; 36\ \textgreater \ 0\; ,\; \; to\; \; 17-5x\ \textless \ 0\\\\ 5x\ \textgreater \ 17\; \; \to \; \; x\ \textgreater \ 3,4$