помогите решить уравнения(10y+2*(7y-2))=(5*(4y+3)+3y) (8*(3m-2)-13+(5*(12+3m)+28
(10y+2*(7y-2))=(5*(4y+3)+3y)
10у+14у-4=20у+15+3у
10у+14у-20у-3у=15+4
у=19
(8*(3m-2)-13=(5*(12+3m)+28
24m-16-13=60+15m+28
24m-15m=60+28+13+16
9m=117
m=117/9
m=13
(10y+2*(7y-2))=(5*(4y+3)+3y) ==> 10y+14y-4=20y+15+3y ==> 24y-4=23y+15 ==>
==> 24y-23y=15+4 ==> y=19
(8*(3m-2)-13+(5*(12+3m)+28)=0 ==> 24m-16-13+60+15m+28=0 ==>
==> 24m+15m = 16+13-60-28 ==> 39m =16+13-60-28=-59 ==> m=-59/39