(6y-4)(y-4)=7(y^2-4y-12)

Question

(6y-4)(y-4)=7(y^2-4y-12)

Answer 1

(6y-4)(y-4)=7(y²-4y-12)
6y²-24y-4y+16=7y²-28y-84
-y²=-100
y²=100
y1=10, y2=-10

Answer 2

(6y - 4)(y - 4) = 7(y^2 - 4y - 12);
6y^2 - 24y - 4y + 16 = 7y^2 - 28y - 84;
6y^2 - 24y - 4y + 16 - 7y^2 + 28y + 84 = 0;
-y^2 + 100 = 0;
-y^2 = -100;
y^2 = 100;
y = +-10;
Ответ: +-10.