(2^x+4)^x-3=0,5^x*4^x-4
2^[(x+4)(x-3)]=2^(-x+2x-8) (x+4)(x-3)=(x-8) x²-3x+4x-12-x+8=0 x²-4=0 (x-2)(x+2)=0 x=2 x=-2