Решите неравенство (x-3)(x+2)(x-1)<=0

Question

Решите неравенство (x-3)(x+2)(x-1)<=0

Answer 1

X=3  x=-2  x=1
           _              +                  _                  +
---------------[-2]---------[1]----------------[3]---------------
x∈(-∞;-2] U [1;3]

Answer 2

(x-3)(x+2)(x-1)≤0
a)x-3=0,x=3, x+2=0,x=-2, x-1=0, x=1
b)-2,1,3
c)x∈(-∞,-2/ : x-3≤0,x+2≤0,x-1≤0, (x-3)(x+2)(x-1)≤0
   x∈(-2,1/: x-3≤0,x+2≥0,x-1≤0, (x-3)(x+2)(x-1)≥0
   x∈(1,3/: x-3≤0, x+2≥0, x-1≥0, (x-3)(x+2)(x-1)≤0
   x∈(3,∞): x-3≥0, x+2≥0, x-1≥0, (x-3)(x+2)(x-1)≥0
d)x∈(-∞,-2/∪/1,3/
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