Sin(2x-2)=2sin(x-1)*cos(x-1)
sin2x-six2=2sin(x-1)*cos(x+1)
2sin(x-1)*cos(x-1)=2sin(x-1)*cos(x+1)
sin(x-1)*cos(x-1)-sin(x-1)*cos(x+1)=0
sin(x-1)*(cos(x-1)-cos(x+1))=0
sin(x-1)=0; cos(x-1)-cos(x+1)=0
x-1=pi*n ; cosx*cos1+sinx*sin1-cosx*cos1+sinx*sin1=0
x=1+pi*n; 2sinx*sin1=0
sinx=0
x=pi*k
[0; 2*pi] [0;2*pi]
x=1+pi*n x=pi*k
n=0, x=1. k=0, x=0
n=1, x=1+pi k=1, x=pi,
k=2, x=2*pi
Ответ: 0, 1, pi, 1+pi, 2pi,