A^3-6a^2+7a , при a= -1/2

Question

A^3-6a^2+7a , при a= -1/2

Answer 1

(-1/2)³-6(-1/2)²+7*(-1/2)=(-1/8)-(6/4)-7/2=-1/8-3/2-7/2=-1/8-12/8-28/8=-41/8=-5  целых 1/8