1) (x-2)^4-(x-2)^2-6=0 2) (x+3)^4+2(x+3)^2-8=0 3 (x+1)^4+(x+1)^2-6=0

Question

1) (x-2)^4-(x-2)^2-6=0
2) (x+3)^4+2(x+3)^2-8=0
3 (x+1)^4+(x+1)^2-6=0

Answer 1

1) (x-2)²=t≥0
t²-t-6=0
t=-2 t=-3
(x-2)²=3
x-2=√3
x-2= -√3
x= -√3 + 2
x= √3 + 2