решите неравенство: х во 2 -11х+24<0

Question

решите неравенство: х во 2 -11х+24<0</p>

Answer 1

х^2-11x+24<0</p>

 P=-11,  q=24

x1+x2=11       x1=3

 

x1*x2=24        x2=8

 

Answer 2

x(3;8)" alt=" x^ 2 -11x+24<0\\D=b^2-4ac=121-96=25 (25=5^2)\\x_1=\frac{-b-\sqrt{D}}{2a}=\frac{11-5}{2}=3;\\x_2=\frac{-b+\sqrt{D}}{2a}=\frac{11+5}{2}=8;\\=>x(3;8)" align="absmiddle" class="latex-formula">