Решите неравенство номер 15
4^(2x) / 16 - 67 * 4^x / 16 + 12 <= 0<br>4^(2x) - 67 * 4^x - 192 <= 0<br>4^x = t t^2 - 67t - 192 <= 0<br>t = (67 +-√(4489 - 768)) / 2 = (67 +- 61) / 2 t = 3 t = 64 + - + -------[3]----------[64]---------- t ∈ [3; 64] x ∈ [log4(3); 3]