3cos 180°+5ctg 270°-2tg 0°+3tg 180°-tg 60°

Question

3cos 180°+5ctg 270°-2tg 0°+3tg 180°-tg 60°

Answer 1

= -3+0-0+0-√3=-3-√3

Объясняю
ctg 270=cos270/sin270=0/-1=0
tg 0=sin0/cos0=0/1=0=tg180