Lim X-1 3x^2-4x+1/2x^2+5x-7
Lim x->1 (3x^2 - 4x + 1)/(2x^2 + 5x - 7) = 0/0 Правило Лопиталя lim x->1 (3x^2 - 4x + 1)' / (2x^2 + 5x - 7) ' = = lim x-> 1 (6x - 4)/(4x + 5) = = (6 - 4)/(4 + 5) = 2/9