㏒₂(3x-10)=5 ㏒₄176-㏒₄2.75

Question

㏒₂(3x-10)=5
㏒₄176-㏒₄2.75

Answer 1

1)log2 (3x-10)=5

(loga (x)=y ⇔x=aˇy)
3x-10=2ˇ5
3x-10=32
3x=32+10
3x=42
x=14
====
2)log4 176 - log4 2,75=log4 176/2,75=log4  64 =3  (4³=64)
Otvet: 3
(log x-log y = log x/y)