ппоизводные номер 1 б в

Y'=((x²+3x-1)*tgx)'=(x²+3x-1)'*tgx+(x²+3x-1)*(tgx)'=(2x+3)*tgx+(x²+3x-1)/cos²x
y'=(2*2+3)*tg2+(2²+3*2-1)/cos²2=7tg2+9/cos²2≈-15,295+51,969≈36,674

$y'=( \frac{x^2}{2-x^2} )'= \frac{(x^2)'(2-x^2)-x^2(2-x^2)'}{(2-x^2)^2}= \frac{2x*(2-x^2)-x^2*(-2x)}{(2-x^2)^2}= \frac{4x-2x^3+2x^3}{(2-x^2)^2}$
$= \frac{4x}{(2-x^2)^2}$
$y'(2)= \frac{4*2}{(2-2^2)^2}= \frac{8}{4}=2$